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lexical::underscore - access your caller's lexical underscore

Author

       Toby Inkster <tobyink@cpan.org>.

Bugs

       Please report any bugs to <http://rt.cpan.org/Dist/Display.html?Queue=lexical-underscore>.

Description

       Starting with Perl 5.10, it is possible to create a lexical version of the Perl default variable $_.
       Certain Perl constructs like the "given" keyword automatically use a lexical $_ rather than the global
       $_.

       It is occasionallly useful for a sub to be able to access its caller's $_ variable regardless of whether
       it was lexical or not. The "(_)" sub prototype is the official way to do so, however there are sometimes
       disadvantages to this; in particular it can only appear as the final required argument in a prototype,
       and there is no way of the sub differentiating between an explicitly passed argument and $_.

       This caused me problems with Scalar::Does, because I wanted to enable the "does" function to be called as
       either:

          does($thing, $role);
          does($role);  # assumes $thing = $_

       With "_" in the prototype, $_ was passed to the function at the end of its argument list; effectively
       "does($role, $thing)", making it impossible to tell which argument was the role.

       Enter "lexical::underscore" which allows you to access your caller's lexical $_ variable as easily as:

          ${lexical::underscore()}

       You can access lexical $_ further up the call stack using:

          ${lexical::underscore($level)}

       If you happen to ask for $_ at a level where no lexical $_ is available, you get the global $_ instead.

       This module does work on Perl 5.8 but as there is no lexical $_, always returns the global $_.

   TechnicalDetails
       The "lexical::underscore" function returns a scalar reference to either a lexical $_ variable somewhere
       up the call stack (using PadWalker magic), or to the global $_ if there was no lexical version.

       Wrapping "lexical::underscore" in "${ ... }" dereferences the scalar reference, allowing you to access
       (and even assign to) it.

Disclaimer Of Warranties

       THIS PACKAGE IS PROVIDED "AS IS" AND WITHOUT ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, WITHOUT
       LIMITATION, THE IMPLIED WARRANTIES OF MERCHANTIBILITY AND FITNESS FOR A PARTICULAR PURPOSE.

perl v5.38.2                                       2024-03-06                           lexical::underscore(3pm)

Name

       lexical::underscore - access your caller's lexical underscore

See Also

       PadWalker.

Synopsis

          use 5.010;
          use lexical::underscore;
          use Test::More;

          sub is_uppercase {
             my $var = @_ ? shift : ${lexical::underscore()};
             return $var eq uc($var);
          }

          my $thing = 'FOO';
          my $works = 0;

          given ( $thing ) {
             when ( is_uppercase ) { $works++ }
          }

          ok($works);
          done_testing();

See Also